Get the free geometry chapter 5 review answer key form. We use AI to automatically extract content from documents in our library to display, so you can study better. From the diagram, we have a line segment that joins the midpoint of two sides of a triangle. Did you find this document useful? © © All Rights Reserved. Description of geometry chapter 5 review answer key. 576648e32a3d8b82ca71961b7a986505.
B. to hours per day. A. median from A B. altitude from A C. perpendicular bisector. Let's set up that equation accordingly: $30 = 2(x)$ Divide each side of the equation by $2$ to solve for $x$: $x = 15$. Save ML Geometry Chapter 5 Review-Test For Later. These review problems are assigned to prepare the students for a quiz or test. Share with Email, opens mail client. You are on page 1. of 5. Description: Copyright. Answer & Explanation. 4. is not shown in this preview. Everything you want to read. Is this content inappropriate? Search inside document. According to the triangle midsegment theorem, if a line segment joins two sides of a triangle at their midpoints, then that line segment is parallel to the third side of that triangle and is half as long as that third side.
0% found this document not useful, Mark this document as not useful. Document Information. Fill & Sign Online, Print, Email, Fax, or Download. Report this Document. Get answers and explanations from our Expert Tutors, in as fast as 20 minutes. Assume that the distribution of time spent on leisure activities by currently employed adults living in households with no children younger than 18 years is normal with a mean of 4. Geometry Chapter 5 Review Write answers in the spaces provided. Sets found in the same folder. Click to expand document information.
Recent flashcard sets. 4 hours per day and a standard deviation of 1. Knowing this information, we can deduce that this line segment is half of the length of the third side to which it is parallel. Reward Your Curiosity. 0% found this document useful (0 votes).
Find the probability that the amount of time spent on leisure activities per day for a randomly chosen person selected from the population of interest (employed adults living in households with no children younger than 18 years) is. Share or Embed Document. E. How much time must be spent on leisure activities by an employed| adult living in households with no children younger than 18 years to be in the group of such adults who spend the highest of time in a day on such activities? You're Reading a Free Preview. In the earlier exercise. A. more than hours per day. Each problem that requires work to support the answer, shows appropriate work that will be acceptable. C. less than 0 hours per day (theoretically, the normal distribution extends from negative infinity to positive infinity, realistically, time spent on leisure activity cannot be negative, so this answer provides an idea of the level of approximation used in modeling this variable).
I have provided the answers to review problems so that the students can check their work against my work. D. more than 24 hours per day (this is similar to part c, except that we are looking at the upper tail of the distribution). PDF, TXT or read online from Scribd. Share this document. Students also viewed.