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Let M be the intersection of the diagonals. Try Numerade free for 7 days. ☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 8.

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Enter your parent or guardian's email address: Already have an account? Gauth Tutor Solution. Also line AC is a transversal of parallel lines BC and DA, so angle ACB is congruent to angle CAD. By definition, line AB is parallel to line CD and line BC is parallel to line DA. Corresponding sides are equal, so AB = CD and BC = DA. Get 5 free video unlocks on our app with code GOMOBILE. Problem 1was given as an in-class group activity. Two segments A C and B D bisect each other at O . Prove that A B C D is a parallelogram. A quadrilateral ABCD is a parallelogram if AB is parallel to CD and BC is parallel to DA. Answered step-by-step. Parallelogram Diagonals. We also know that angle AMB = angle CMD by vertical angles. ABCD is a parallelogram with AC and BD as the diagonals intersecting at O. OA = 3 cm.

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Proposition: If ABCD is a parallelogram, its opposite sides are equal. B) Prove that a parallelogram with perpendicular diagonals is a rhombus. Students also viewed. Thus triangle ABO is similar to triangle CDO. ☛ Related Questions: - Diagonals of a rhombus are equal and perpendicular to each other. If OP = 4 cm and OS = 3 cm, determine the lengths of PR and QS.

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Extra credit opportunity. Also, by vertical angles, angle AOB = angle COD. Line-segments and bisect each other at. Thus we see that two opposite sides of ABCD are parallel. Therefore, the lengths of AC and BD are 6 cm and 4 cm.

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Doubtnut helps with homework, doubts and solutions to all the questions. Is A.... visual curriculum. High accurate tutors, shorter answering time. Given: AC and BD bisect each other: Prove: BC 2 AD. These are two corresponding sides of the similar triangles, so the two triangles ABO and CDO are congruent. Then the technician places the metal into a graduated glass cylinder of radius 4 cm that contains a nonreactive liquid. We solved the question! Unlimited access to all gallery answers. Since line AC is a transversal of the parallel lines AB and CD, then angle OAB = angle CAB = angle ACD = angle OCD. We will prove that triangle ABC is congruent to triangle CDA by ASA. Given ac and bd bisect each other at o in terms. Gauthmath helper for Chrome.

Since there was nothing special about those two side, using the same argument, we can also conclude that BC and DA are parallel, so by definition ABCD is a parallelogram. We know from this that MA = MC and MB = MD. Given ac and bd bisect each other at o j. Prove that a quadrilateral is a parallelogram if and only if the diagonals bisect each other. This follows from that result. We must prove that AB = CD and BC = DA. The time allotted as 25 minutes.

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