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I hire a car which costs me £50 and then a further 10p for every mile that I cover. Fblpn, 5x-y >= 5 and y=5. There are three types of equations that you must be able to interpret and find an equation for from a graph: 1) squared function. When x is equal to 1, y is less than 7. Learn how to graph two-variable linear inequalities like y≤4x+3. Since the car park is the numbers of cars and buses must satisfy the following: We can simplify this to: We are also told that there must be at least 5 buses and the number of cars will be at least twice that of buses. Which inequality represents the graph shown below. Plot this problem graphically using inequalities and find the largest number of buses that can be parked. Where the shaded areas overlap, that is your solution. So let me just graph-- just for fun-- let me graph y is equal to-- this is the same thing as negative 1/2 minus 6. Sal did this to show you what this means.
Solved by verified expert. Then what does the -3 signify/refer to when I put this inequality into slop intercept form to graph it......? Oh, that should be an x there, negative 1/2 x minus 6. Because in that situation, this wouldn't apply, and we would just have that. When x is equal to 0, then that means y is going to be less than 0 plus 3. y is less than 3. Draw the line on the graph (you can use the video of the graph since its the same equation except I'm using a less than instead of less than or equal to). So that's the line of y is equal to negative 1/2 x minus 6. Finding the gradient of a curve by graphing. If you evaluate 4x plus 3, you're going to get the point on the line. Y=0x+5 So the slope is 0 (a horizontal line) that crosses the y axis at 5. Therefore, a point on the line which is equal is neither of these things.
So it's going to be not that point-- in fact, you draw an open circle there-- because you can't include the point of negative 1/2 x minus 6. And the convention to do that is to actually make the line a dashed line. So if we were to graph it, that is my vertical axis, that is my horizontal axis. Let's do one like that. To graph the inequality, graph the equation of the boundary.
So a good way to start-- the way I like to start these problems-- is to just graph this equation right here. Let's graph ourselves some inequalities. It's going to look something like that. A bus takes up so buses will take up of the car park. I like the point (2, 0). If we go 1 back in the x-direction, we're going to go down 4. If I have something like y>-3 and the question says to 'graph the inequality in the coordinate plane'. What about all these where y ix less than 4x plus 3?
Which means if we go 1 in the x-direction, we're going to go up 4 in the y. And we're not going to include the line. The coordinates that satisfy our equality are all of this yellow stuff that I'm shading above the line. And the reason why I did that on this first example problem is because we know how to graph that. You would then subtract 3 from both sides of the equation to get -3x<=-4.
How do I write the slope if the line goes straight up (is vertical) and how do I write it's equation if the y-intercept is not given but I have an x-intercept? So I'm turning that solid line into a dashed line to show that it's just a boundary, but it's not included in the coordinates that satisfy our inequality. More or less than||Dotted|. You evaluate negative 1/2 or negative x over 2 minus 6, you're going to get this point over here.
To do this we simply plot the two separately and shade the incorrect regions. By clicking Sign up you accept Numerade's Terms of Service and Privacy Policy. If the inequality has a symbol of greater than or equal to or greater than you shade above the line.